{"id":7725,"date":"2024-07-09T07:01:03","date_gmt":"2024-07-08T23:01:03","guid":{"rendered":""},"modified":"2024-07-09T07:01:03","modified_gmt":"2024-07-08T23:01:03","slug":"\u4e8c\u5206\u6cd5\u6c42\u591a\u9879\u5f0f\u5355\u6839c\u8bed\u8a00\u9898_\u5982\u4f55\u7528\u4e8c\u5206\u6cd5\u6c42\u8fd1\u4f3c\u89e3","status":"publish","type":"post","link":"https:\/\/mushiming.com\/7725.html","title":{"rendered":"\u4e8c\u5206\u6cd5\u6c42\u591a\u9879\u5f0f\u5355\u6839c\u8bed\u8a00\u9898_\u5982\u4f55\u7528\u4e8c\u5206\u6cd5\u6c42\u8fd1\u4f3c\u89e3"},"content":{"rendered":"
7-18 \u4e8c\u5206\u6cd5\u6c42\u591a\u9879\u5f0f\u5355\u6839<\/p>\n
\u5206\u6570 20<\/p>\n
\u4f5c\u8005 \u6768\u8d77\u5e06<\/p>\n
\u5355\u4f4d \u6d59\u5927\u57ce\u5e02\u5b66\u9662<\/p>\n
\n\u9898\u76ee\uff1a<\/p>\n
\u4e8c\u5206\u6cd5\u6c42\u51fd\u6570\u6839\u7684\u539f\u7406\u4e3a\uff1a\u5982\u679c\u8fde\u7eed\u51fd\u6570f(x)\u5728\u533a\u95f4[a,b]\u7684\u4e24\u4e2a\u7aef\u70b9\u53d6\u503c\u5f02\u53f7\uff0c\u5373f(a)f(b)<0\uff0c\u5219\u5b83\u5728\u8fd9\u4e2a\u533a\u95f4\u5185\u81f3\u5c11\u5b58\u57281\u4e2a\u6839r\uff0c\u5373f(r)=0\u3002<\/p>\n
\u4e8c\u5206\u6cd5\u7684\u6b65\u9aa4\u4e3a\uff1a<\/p>\n
\n
- \u68c0\u67e5\u533a\u95f4\u957f\u5ea6\uff0c\u5982\u679c\u5c0f\u4e8e\u7ed9\u5b9a\u9608\u503c\uff0c\u5219\u505c\u6b62\uff0c\u8f93\u51fa\u533a\u95f4\u4e2d\u70b9(a+b)\/2\uff1b\u5426\u5219<\/li>\n
- \u5982\u679cf(a)f(b)<0\uff0c\u5219\u8ba1\u7b97\u4e2d\u70b9\u7684\u503cf((a+b)\/2)\uff1b<\/li>\n
- \u5982\u679cf((a+b)\/2)\u6b63\u597d\u4e3a0\uff0c\u5219(a+b)\/2\u5c31\u662f\u8981\u6c42\u7684\u6839\uff1b\u5426\u5219<\/li>\n
- \u5982\u679cf((a+b)\/2)\u4e0ef(a)\u540c\u53f7\uff0c\u5219\u8bf4\u660e\u6839\u5728\u533a\u95f4[(a+b)\/2,b]\uff0c\u4ee4a=(a+b)\/2\uff0c\u91cd\u590d\u5faa\u73af\uff1b<\/li>\n
- \u5982\u679cf((a+b)\/2)\u4e0ef(b)\u540c\u53f7\uff0c\u5219\u8bf4\u660e\u6839\u5728\u533a\u95f4[a,(a+b)\/2]\uff0c\u4ee4b=(a+b)\/2\uff0c\u91cd\u590d\u5faa\u73af\u3002<\/li>\n<\/ul>\n
\u672c\u9898\u76ee\u8981\u6c42\u7f16\u5199\u7a0b\u5e8f\uff0c\u8ba1\u7b97\u7ed9\u5b9a3\u9636\u591a\u9879\u5f0ff(x)=a3\u200bx3+a2\u200bx2+a1\u200bx+a0\u200b\u5728\u7ed9\u5b9a\u533a\u95f4[a,b]\u5185\u7684\u6839\u3002<\/p>\n
\u8f93\u5165\u683c\u5f0f\uff1a<\/h4>\n
\u8f93\u5165\u5728\u7b2c1\u884c\u4e2d\u987a\u5e8f\u7ed9\u51fa\u591a\u9879\u5f0f\u76844\u4e2a\u7cfb\u6570a3\u200b\u3001a2\u200b\u3001a1\u200b\u3001a0\u200b\uff0c\u5728\u7b2c2\u884c\u4e2d\u987a\u5e8f\u7ed9\u51fa\u533a\u95f4\u7aef\u70b9a\u548cb\u3002\u9898\u76ee\u4fdd\u8bc1\u591a\u9879\u5f0f\u5728\u7ed9\u5b9a\u533a\u95f4\u5185\u5b58\u5728\u552f\u4e00\u5355\u6839\u3002<\/p>\n
\u8f93\u51fa\u683c\u5f0f\uff1a<\/h4>\n
\u5728\u4e00\u884c\u4e2d\u8f93\u51fa\u8be5\u591a\u9879\u5f0f\u5728\u8be5\u533a\u95f4\u5185\u7684\u6839\uff0c\u7cbe\u786e\u5230\u5c0f\u6570\u70b9\u540e2\u4f4d\u3002<\/p>\n
\u8f93\u5165\u6837\u4f8b\uff1a<\/h4>\n
3 -1 -3 1 -0.5 0.5 <\/code><\/pre>\n
\u8f93\u51fa\u6837\u4f8b\uff1a<\/h4>\n
0.33<\/code><\/pre>\n<\/p>\n<\/blockquote>\n
<\/p>\n
\u5b8c\u6574\u4ee3\u7801<\/h2>\n
#include<stdio.h> #include<stdlib.h> #define f(x) (a3*x*x*x+a2*x*x+a1*x+a0) int main() { \/\/int x = 0; double a0,a1, a2, a3; double a, b; double result = 0, mid=0; scanf(\"%lf %lf %lf %lf\", &a3, &a2, &a1, &a0); scanf(\"%lf %lf\", &a, &b); while ( b>=a &&f(a) * f(b) <= 0) { if (b - a < 0.01)\/\/\u68c0\u67e5\u533a\u95f4\u957f\u5ea6\uff0c\u5982\u679c\u5c0f\u4e8e\u7ed9\u5b9a\u9608\u503c\uff0c\u5219\u505c\u6b62\uff0c\u8f93\u51fa\u533a\u95f4\u4e2d\u70b9(a+b)\/2\uff1b { result = (a+b) \/ 2; break; } double mid = (a + b) \/ 2;\/\/\u5982\u679cf(a)f(b) < 0\uff0c\u5219\u8ba1\u7b97\u4e2d\u70b9\u7684\u503cf((a + b) \/ 2)\uff1b if (f(mid) == 0)\/\/\u5982\u679cf((a+b)\/2)\u6b63\u597d\u4e3a0\uff0c\u5219(a+b)\/2\u5c31\u662f\u8981\u6c42\u7684\u6839\uff1b\u5426\u5219 { result = mid; break; } else if (f(mid)*f(a) > 0)\/\/\u5982\u679cf((a+b)\/2)\u4e0ef(a)\u540c\u53f7\uff0c\u5219\u8bf4\u660e\u6839\u5728\u533a\u95f4[(a+b)\/2,b]\uff0c\u4ee4a=(a+b)\/2\uff0c\u91cd\u590d\u5faa\u73af\uff1b { a = mid; } else if(f(mid)*f(b)>0)\/\/\u5982\u679cf((a+b)\/2)\u4e0ef(b)\u540c\u53f7\uff0c\u5219\u8bf4\u660e\u6839\u5728\u533a\u95f4[a,(a+b)\/2]\uff0c\u4ee4b=(a+b)\/2\uff0c\u91cd\u590d\u5faa\u73af\u3002 { b = mid; } } printf(\"%.2f\", result);\/\/\u5728\u4e00\u884c\u4e2d\u8f93\u51fa\u8be5\u591a\u9879\u5f0f\u5728\u8be5\u533a\u95f4\u5185\u7684\u6839\uff0c\u7cbe\u786e\u5230\u5c0f\u6570\u70b9\u540e2\u4f4d\u3002 return 0; }<\/code><\/pre>\n
<\/p>\n
<\/p>\n
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